What are the solutions to the equation x^2+12x+26=0 ?

The solutions to the equation x^2+12x+26=0 are x=-6+sqrt(10),x=-6-sqrt(10)

Find the zeros of x^2+12x+26=0

The zeros of x^2+12x+26=0 are x=-6+sqrt(10),x=-6-sqrt(10)

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x^{2} + 12 x + 26 = 0

x = - 6 + 10, x = - 6 - 10

Decimal Notation

x = - 2.83772 \dots, x = - 9.16227 \dots

Solution steps

x^{2} + 12 x + 26 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot 26}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot 26 = 210

x_{1, 2} = \frac{- 12 \pm 2 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 12 + 2 10}{2 \cdot 1}, x_{2} = \frac{- 12 - 2 10}{2 \cdot 1}

x = \frac{- 12 + 2 10}{2 \cdot 1} : - 6 + 10

x = \frac{- 12 - 2 10}{2 \cdot 1} : - 6 - 10

The solutions to the quadratic equation are:

x = - 6 + 10, x = - 6 - 10

\frac{3}{- 6}

- 12 x^{2} + 45 x + 12

6 x^{- 1} y^{5} \cdot 4 x^{- 4} y^{- 2}

6 x + 9 = 4 x + 25

0 = x^{2} + 16

What are the solutions to the equation x^2+12x+26=0 ?
The solutions to the equation x^2+12x+26=0 are x=-6+sqrt(10),x=-6-sqrt(10)
Find the zeros of x^2+12x+26=0
The zeros of x^2+12x+26=0 are x=-6+sqrt(10),x=-6-sqrt(10)