What are the solutions to the equation x^2-8x+13=0 ?

The solutions to the equation x^2-8x+13=0 are x=4+sqrt(3),x=4-sqrt(3)

Find the zeros of x^2-8x+13=0

The zeros of x^2-8x+13=0 are x=4+sqrt(3),x=4-sqrt(3)

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x^{2} - 8 x + 13 = 0

x = 4 + 3, x = 4 - 3

Solution steps

x^{2} - 8 x + 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 13}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 13 = 23

x_{1, 2} = \frac{- ( - 8 ) \pm 2 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2 3}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 2 3}{2 \cdot 1}

x = \frac{- ( - 8 ) + 2 3}{2 \cdot 1} : 4 + 3

x = \frac{- ( - 8 ) - 2 3}{2 \cdot 1} : 4 - 3

The solutions to the quadratic equation are:

x = 4 + 3, x = 4 - 3

(\frac{1}{x ^{2} - 5 x - 36})^{\frac{1}{2}}

2 c^{3} + 14 c^{2} - 16 c

- y^{2} - 4 y + 12 = 0

\frac{5}{12} + \frac{1}{3} - \frac{2}{5}

(3 x - 4)^{2} = 42

What are the solutions to the equation x^2-8x+13=0 ?
The solutions to the equation x^2-8x+13=0 are x=4+sqrt(3),x=4-sqrt(3)
Find the zeros of x^2-8x+13=0
The zeros of x^2-8x+13=0 are x=4+sqrt(3),x=4-sqrt(3)