What are the solutions to the equation (3x-4)^2=42 ?

The solutions to the equation (3x-4)^2=42 are x=(sqrt(42)+4)/3 ,x=(-sqrt(42)+4)/3

Find the zeros of (3x-4)^2=42

The zeros of (3x-4)^2=42 are x=(sqrt(42)+4)/3 ,x=(-sqrt(42)+4)/3

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(3 x - 4)^{2} = 42

x = \frac{42 + 4}{3}, x = \frac{- 42 + 4}{3}

Solution steps

(3 x - 4)^{2} = 42

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x - 4 = 42 : x = \frac{42 + 4}{3}

Solve

3 x - 4 = - 42 : x = \frac{- 42 + 4}{3}

The solutions to the quadratic equation are:

x = \frac{42 + 4}{3}, x = \frac{- 42 + 4}{3}

x^{2} - 60 x + 851

- x^{2} + 25 = 0

\frac{0.8}{2 ^{6}}

lo g_{3} ((x - 1) (2 - 3 x)) < 2

\frac{( ( x + h ) + 6 ) - ( x + 6 )}{h}

What are the solutions to the equation (3x-4)^2=42 ?
The solutions to the equation (3x-4)^2=42 are x=(sqrt(42)+4)/3 ,x=(-sqrt(42)+4)/3
Find the zeros of (3x-4)^2=42
The zeros of (3x-4)^2=42 are x=(sqrt(42)+4)/3 ,x=(-sqrt(42)+4)/3