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Popular >

4y^2-28y=0

Solution

4 y^{2} - 28 y = 0

Solution

y = 7, y = 0

Solution steps

4 y^{2} - 28 y = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 28 ) \pm ( - 28 ) ^{2} - 4 \cdot 4 \cdot 0}{2 \cdot 4}

(- 28)^{2} - 4 \cdot 4 \cdot 0 = 28

y_{1, 2} = \frac{- ( - 28 ) \pm 28}{2 \cdot 4}

Separate the solutions

y_{1} = \frac{- ( - 28 ) + 28}{2 \cdot 4}, y_{2} = \frac{- ( - 28 ) - 28}{2 \cdot 4}

y = \frac{- ( - 28 ) + 28}{2 \cdot 4} : 7

y = \frac{- ( - 28 ) - 28}{2 \cdot 4} : 0

The solutions to the quadratic equation are:

y = 7, y = 0

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Frequently Asked Questions (FAQ)

What are the solutions to the equation 4y^2-28y=0 ?
The solutions to the equation 4y^2-28y=0 are y=7,y=0
Find the zeros of 4y^2-28y=0
The zeros of 4y^2-28y=0 are y=7,y=0