What are the solutions to the equation 2(x+1)^2=36 ?

The solutions to the equation 2(x+1)^2=36 are x=3sqrt(2)-1,x=-3sqrt(2)-1

Find the zeros of 2(x+1)^2=36

The zeros of 2(x+1)^2=36 are x=3sqrt(2)-1,x=-3sqrt(2)-1

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2 (x + 1)^{2} = 36

x = 32 - 1, x = - 32 - 1

Decimal Notation

x = 3.24264 \dots, x = - 5.24264 \dots

Solution steps

2 (x + 1)^{2} = 36

Divide both sides by

2

(x + 1)^{2} = 18

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 1 = 18 : x = 32 - 1

Solve

x + 1 = - 18 : x = - 32 - 1

The solutions to the quadratic equation are:

x = 32 - 1, x = - 32 - 1

\frac{( \frac{5}{2} ) ^{3}}{( \frac{2}{5} ) ^{- 4}}

∣ 2 x + 3 ∣ > - 3

5 x - 3 = \frac{1}{4} x + 2

\frac{7}{6} + \frac{4}{6}

2 y^{2} = 2 π y

What are the solutions to the equation 2(x+1)^2=36 ?
The solutions to the equation 2(x+1)^2=36 are x=3sqrt(2)-1,x=-3sqrt(2)-1
Find the zeros of 2(x+1)^2=36
The zeros of 2(x+1)^2=36 are x=3sqrt(2)-1,x=-3sqrt(2)-1