What are the solutions to the equation 100-p^2=2p+20 ?

The solutions to the equation 100-p^2=2p+20 are p=-10,p=8

Find the zeros of 100-p^2=2p+20

The zeros of 100-p^2=2p+20 are p=-10,p=8

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100 - p^{2} = 2 p + 20

p = - 10, p = 8

Solution steps

100 - p^{2} = 2 p + 20

Move

20

to the left side

- p^{2} + 80 = 2 p

Move

2 p

to the left side

- p^{2} + 80 - 2 p = 0

Write in the standard form

a x^{2} + b x + c = 0

- p^{2} - 2 p + 80 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 ( - 1 ) \cdot 80}{2 ( - 1 )}

(- 2)^{2} - 4 (- 1) \cdot 80 = 18

p_{1, 2} = \frac{- ( - 2 ) \pm 18}{2 ( - 1 )}

Separate the solutions

p_{1} = \frac{- ( - 2 ) + 18}{2 ( - 1 )}, p_{2} = \frac{- ( - 2 ) - 18}{2 ( - 1 )}

p = \frac{- ( - 2 ) + 18}{2 ( - 1 )} : - 10

p = \frac{- ( - 2 ) - 18}{2 ( - 1 )} : 8

The solutions to the quadratic equation are:

p = - 10, p = 8

2 x - 5 = 11

4 x^{2} + 12 x - 9 y^{2} + 18 y

0 = - 3 x^{2} + 14 xx - 8

x^{2} y + 3 x y

25 - 5 + 45 + 3

What are the solutions to the equation 100-p^2=2p+20 ?
The solutions to the equation 100-p^2=2p+20 are p=-10,p=8
Find the zeros of 100-p^2=2p+20
The zeros of 100-p^2=2p+20 are p=-10,p=8