What are the solutions to the equation 12x^2-48x+64=0 ?

The solutions to the equation 12x^2-48x+64=0 are x=2+i(2sqrt(3))/3 ,x=2-i(2sqrt(3))/3

Find the zeros of 12x^2-48x+64=0

The zeros of 12x^2-48x+64=0 are x=2+i(2sqrt(3))/3 ,x=2-i(2sqrt(3))/3

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12 x^{2} - 48 x + 64 = 0

x = 2 + i \frac{2 3}{3}, x = 2 - i \frac{2 3}{3}

Solution steps

12 x^{2} - 48 x + 64 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 48 ) \pm ( - 48 ) ^{2} - 4 \cdot 12 \cdot 64}{2 \cdot 12}

Simplify

(- 48)^{2} - 4 \cdot 12 \cdot 64 : 163 i

x_{1, 2} = \frac{- ( - 48 ) \pm 16 3 i}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 48 ) + 16 3 i}{2 \cdot 12}, x_{2} = \frac{- ( - 48 ) - 16 3 i}{2 \cdot 12}

x = \frac{- ( - 48 ) + 16 3 i}{2 \cdot 12} : 2 + i \frac{2 3}{3}

x = \frac{- ( - 48 ) - 16 3 i}{2 \cdot 12} : 2 - i \frac{2 3}{3}

The solutions to the quadratic equation are:

x = 2 + i \frac{2 3}{3}, x = 2 - i \frac{2 3}{3}

5 x^{2} - 3 x - 14 = 0

- x^{2} + 12 - 8 x = - 3

x^{3} + x - 10

3 x^{2} = 6 x - 9

\frac{y - x ( \frac{x}{y} )}{y ^{2}}

What are the solutions to the equation 12x^2-48x+64=0 ?
The solutions to the equation 12x^2-48x+64=0 are x=2+i(2sqrt(3))/3 ,x=2-i(2sqrt(3))/3
Find the zeros of 12x^2-48x+64=0
The zeros of 12x^2-48x+64=0 are x=2+i(2sqrt(3))/3 ,x=2-i(2sqrt(3))/3