What are the solutions to the equation x^2+4x+4=6 ?

The solutions to the equation x^2+4x+4=6 are x=-2+sqrt(6),x=-2-sqrt(6)

Find the zeros of x^2+4x+4=6

The zeros of x^2+4x+4=6 are x=-2+sqrt(6),x=-2-sqrt(6)

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x^{2} + 4 x + 4 = 6

x = - 2 + 6, x = - 2 - 6

Decimal Notation

x = 0.44948 \dots, x = - 4.44948 \dots

Solution steps

x^{2} + 4 x + 4 = 6

Move

6

to the left side

x^{2} + 4 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 2) = 26

x_{1, 2} = \frac{- 4 \pm 2 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 2 6}{2 \cdot 1}, x_{2} = \frac{- 4 - 2 6}{2 \cdot 1}

x = \frac{- 4 + 2 6}{2 \cdot 1} : - 2 + 6

x = \frac{- 4 - 2 6}{2 \cdot 1} : - 2 - 6

The solutions to the quadratic equation are:

x = - 2 + 6, x = - 2 - 6

6 x^{2} - 12 x - 90 = 152

\frac{x + 1}{1 - x} + \frac{x - 1}{x} < 2

2 x + \frac{5}{3} > \frac{2}{5} x - 1

64 - - 289

5 x + 1 = 3 x - 4

What are the solutions to the equation x^2+4x+4=6 ?
The solutions to the equation x^2+4x+4=6 are x=-2+sqrt(6),x=-2-sqrt(6)
Find the zeros of x^2+4x+4=6
The zeros of x^2+4x+4=6 are x=-2+sqrt(6),x=-2-sqrt(6)