What are the solutions to the equation x^2-32x=0 ?

The solutions to the equation x^2-32x=0 are x=32,x=0

Find the zeros of x^2-32x=0

The zeros of x^2-32x=0 are x=32,x=0

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x^{2} - 32 x = 0

x = 32, x = 0

Solution steps

x^{2} - 32 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 32 ) \pm ( - 32 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 32)^{2} - 4 \cdot 1 \cdot 0 = 32

x_{1, 2} = \frac{- ( - 32 ) \pm 32}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 32 ) + 32}{2 \cdot 1}, x_{2} = \frac{- ( - 32 ) - 32}{2 \cdot 1}

x = \frac{- ( - 32 ) + 32}{2 \cdot 1} : 32

x = \frac{- ( - 32 ) - 32}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 32, x = 0

3 h^{2} + 53 = - 19 - 30 h

\frac{8.25 \cdot 1 0 ^{- 12}}{3.01 \cdot 1 0 ^{12}}

- x - 6 \leq - 3 or - 4 x + 3 > - 1

- 2 (4 x + 3) = 5 + 3 x

(2 2 - 2) x^{2} + (8) x + (1 + 2) = 0

What are the solutions to the equation x^2-32x=0 ?
The solutions to the equation x^2-32x=0 are x=32,x=0
Find the zeros of x^2-32x=0
The zeros of x^2-32x=0 are x=32,x=0