What are the solutions to the equation 3h^2+53=-19-30h ?

The solutions to the equation 3h^2+53=-19-30h are h=-4,h=-6

Find the zeros of 3h^2+53=-19-30h

The zeros of 3h^2+53=-19-30h are h=-4,h=-6

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3 h^{2} + 53 = - 19 - 30 h

h = - 4, h = - 6

Solution steps

3 h^{2} + 53 = - 19 - 30 h

Move

30 h

to the left side

3 h^{2} + 53 + 30 h = - 19

Move

19

to the left side

3 h^{2} + 30 h + 72 = 0

Solve with the quadratic formula

h_{1, 2} = \frac{- 30 \pm 3 0 ^{2} - 4 \cdot 3 \cdot 72}{2 \cdot 3}

3 0^{2} - 4 \cdot 3 \cdot 72 = 6

h_{1, 2} = \frac{- 30 \pm 6}{2 \cdot 3}

Separate the solutions

h_{1} = \frac{- 30 + 6}{2 \cdot 3}, h_{2} = \frac{- 30 - 6}{2 \cdot 3}

h = \frac{- 30 + 6}{2 \cdot 3} : - 4

h = \frac{- 30 - 6}{2 \cdot 3} : - 6

The solutions to the quadratic equation are:

h = - 4, h = - 6

\frac{8.25 \cdot 1 0 ^{- 12}}{3.01 \cdot 1 0 ^{12}}

- x - 6 \leq - 3 or - 4 x + 3 > - 1

- 2 (4 x + 3) = 5 + 3 x

(2 2 - 2) x^{2} + (8) x + (1 + 2) = 0

3 x^{2} - x + 1 = 0

What are the solutions to the equation 3h^2+53=-19-30h ?
The solutions to the equation 3h^2+53=-19-30h are h=-4,h=-6
Find the zeros of 3h^2+53=-19-30h
The zeros of 3h^2+53=-19-30h are h=-4,h=-6