What is factor 3y^2+40y-28 ?

The solution to factor 3y^2+40y-28 is (3y-2)(y+14)

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factor 3y^2+40y-28

factor

3 y^{2} + 40 y - 28

(3 y - 2) (y + 14)

Solution steps

3 y^{2} + 40 y - 28

Break the expression into groups

= (3 y^{2} - 2 y) + (42 y - 28)

Factor out

y

from

3 y^{2} - 2 y : y (3 y - 2)

Factor out

14

from

42 y - 28 : 14 (3 y - 2)

= y (3 y - 2) + 14 (3 y - 2)

Factor out common term

3 y - 2

= (3 y - 2) (y + 14)

5 (6 - 2 y) + 4 y = 6

\frac{6 ^{7}}{6 ^{4}}

\frac{n - 1}{10 n - 10}

x^{2} - 7 x + 4 = 0

\frac{20 ( 5 + 3 ( 13 ) )}{1 + 0.04 ( 13 )}