What are the solutions to the equation 4x^2+9=12x ?

The solutions to the equation 4x^2+9=12x are x= 3/2

Find the zeros of 4x^2+9=12x

The zeros of 4x^2+9=12x are x= 3/2

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4 x^{2} + 9 = 12 x

x = \frac{3}{2}

Decimal Notation

x = 1.5

Solution steps

4 x^{2} + 9 = 12 x

Move

12 x

to the left side

4 x^{2} + 9 - 12 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} - 12 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 4 \cdot 9}{2 \cdot 4}

(- 12)^{2} - 4 \cdot 4 \cdot 9 = 0

x_{1, 2} = \frac{- ( - 12 ) \pm 0}{2 \cdot 4}

x = \frac{- ( - 12 )}{2 \cdot 4}

\frac{- ( - 12 )}{2 \cdot 4} = \frac{3}{2}

x = \frac{3}{2}

The solution to the quadratic equation is:

x = \frac{3}{2}

6 s t + 9 t - 10 s - 15

(m + 2)^{2} - (m + 2) + mn \cdot (n + 2) + 2 n (n + 2)

5^{2} + 5^{2}

m^{3} - 12 m + 16

x^{2} + 48 = 0

What are the solutions to the equation 4x^2+9=12x ?
The solutions to the equation 4x^2+9=12x are x= 3/2
Find the zeros of 4x^2+9=12x
The zeros of 4x^2+9=12x are x= 3/2