What are the solutions to the equation x^2+48=0 ?

The solutions to the equation x^2+48=0 are x=4sqrt(3)i,x=-4sqrt(3)i

Find the zeros of x^2+48=0

The zeros of x^2+48=0 are x=4sqrt(3)i,x=-4sqrt(3)i

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x^{2} + 48 = 0

x = 43 i, x = - 43 i

Solution steps

x^{2} + 48 = 0

Move

48

to the right side

x^{2} = - 48

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 48, x = - - 48

- 48 = 43 i

- - 48 = - 43 i

x = 43 i, x = - 43 i

6 x^{2} + 5 x - 4 = 0

\frac{d}{d t} (\frac{m - t}{n})

\frac{w + 4}{3} - \frac{2 w - 1}{5} = 1

- 5 x + 12 = 5 x + 12

∣ x - 2 ∣^{2} - 2 ∣ x - 2 ∣ - 15 > 0

What are the solutions to the equation x^2+48=0 ?
The solutions to the equation x^2+48=0 are x=4sqrt(3)i,x=-4sqrt(3)i
Find the zeros of x^2+48=0
The zeros of x^2+48=0 are x=4sqrt(3)i,x=-4sqrt(3)i