What are the solutions to the equation 6x^2+5x-4=0 ?

The solutions to the equation 6x^2+5x-4=0 are x= 1/2 ,x=-4/3

Find the zeros of 6x^2+5x-4=0

The zeros of 6x^2+5x-4=0 are x= 1/2 ,x=-4/3

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6 x^{2} + 5 x - 4 = 0

x = \frac{1}{2}, x = - \frac{4}{3}

Solution steps

6 x^{2} + 5 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 6 ( - 4 )}{2 \cdot 6}

5^{2} - 4 \cdot 6 (- 4) = 11

x_{1, 2} = \frac{- 5 \pm 11}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 5 + 11}{2 \cdot 6}, x_{2} = \frac{- 5 - 11}{2 \cdot 6}

x = \frac{- 5 + 11}{2 \cdot 6} : \frac{1}{2}

x = \frac{- 5 - 11}{2 \cdot 6} : - \frac{4}{3}

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - \frac{4}{3}

\frac{d}{d t} (\frac{m - t}{n})

\frac{w + 4}{3} - \frac{2 w - 1}{5} = 1

- 5 x + 12 = 5 x + 12

∣ x - 2 ∣^{2} - 2 ∣ x - 2 ∣ - 15 > 0

k^{2} + 17 k + 66

What are the solutions to the equation 6x^2+5x-4=0 ?
The solutions to the equation 6x^2+5x-4=0 are x= 1/2 ,x=-4/3
Find the zeros of 6x^2+5x-4=0
The zeros of 6x^2+5x-4=0 are x= 1/2 ,x=-4/3