What are the solutions to the equation x^2+15x+50=0 ?

The solutions to the equation x^2+15x+50=0 are x=-5,x=-10

Find the zeros of x^2+15x+50=0

The zeros of x^2+15x+50=0 are x=-5,x=-10

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x^{2} + 15 x + 50 = 0

x = - 5, x = - 10

Solution steps

x^{2} + 15 x + 50 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 1 \cdot 50}{2 \cdot 1}

1 5^{2} - 4 \cdot 1 \cdot 50 = 5

x_{1, 2} = \frac{- 15 \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 15 + 5}{2 \cdot 1}, x_{2} = \frac{- 15 - 5}{2 \cdot 1}

x = \frac{- 15 + 5}{2 \cdot 1} : - 5

x = \frac{- 15 - 5}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

x = - 5, x = - 10

y^{2} - 10 y = - 20

s^{2} + 5 s = 0

3 x^{2} - 5 x - 2 > 0

x^{2} + x - 12 > 0

(x^{2} - 16) - (x - 4) (3 x + 5)

What are the solutions to the equation x^2+15x+50=0 ?
The solutions to the equation x^2+15x+50=0 are x=-5,x=-10
Find the zeros of x^2+15x+50=0
The zeros of x^2+15x+50=0 are x=-5,x=-10