What are the solutions to the equation 4p^2+4p-7=0 ?

The solutions to the equation 4p^2+4p-7=0 are p=(-1+2sqrt(2))/2 ,p=-(1+2sqrt(2))/2

Find the zeros of 4p^2+4p-7=0

The zeros of 4p^2+4p-7=0 are p=(-1+2sqrt(2))/2 ,p=-(1+2sqrt(2))/2

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4 p^{2} + 4 p - 7 = 0

p = \frac{- 1 + 2 2}{2}, p = - \frac{1 + 2 2}{2}

Decimal Notation

p = 0.91421 \dots, p = - 1.91421 \dots

Solution steps

4 p^{2} + 4 p - 7 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 4 ( - 7 )}{2 \cdot 4}

4^{2} - 4 \cdot 4 (- 7) = 82

p_{1, 2} = \frac{- 4 \pm 8 2}{2 \cdot 4}

Separate the solutions

p_{1} = \frac{- 4 + 8 2}{2 \cdot 4}, p_{2} = \frac{- 4 - 8 2}{2 \cdot 4}

p = \frac{- 4 + 8 2}{2 \cdot 4} : \frac{- 1 + 2 2}{2}

p = \frac{- 4 - 8 2}{2 \cdot 4} : - \frac{1 + 2 2}{2}

The solutions to the quadratic equation are:

p = \frac{- 1 + 2 2}{2}, p = - \frac{1 + 2 2}{2}

\frac{x}{7} - 8 = - 7

2 x^{2} - 8 x - 24

- \frac{1}{3} - \frac{1}{3}

a^{2} + 7 a + 7 = 0

x^{2} = (5 \cdot 1 0^{- 9} - x) \cdot 1.862 \cdot 1 0^{- 10}

What are the solutions to the equation 4p^2+4p-7=0 ?
The solutions to the equation 4p^2+4p-7=0 are p=(-1+2sqrt(2))/2 ,p=-(1+2sqrt(2))/2
Find the zeros of 4p^2+4p-7=0
The zeros of 4p^2+4p-7=0 are p=(-1+2sqrt(2))/2 ,p=-(1+2sqrt(2))/2