What are the solutions to the equation a^2+7a+7=0 ?

The solutions to the equation a^2+7a+7=0 are a=(-7+sqrt(21))/2 ,a=(-7-sqrt(21))/2

Find the zeros of a^2+7a+7=0

The zeros of a^2+7a+7=0 are a=(-7+sqrt(21))/2 ,a=(-7-sqrt(21))/2

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a^{2} + 7 a + 7 = 0

a = \frac{- 7 + 21}{2}, a = \frac{- 7 - 21}{2}

Decimal Notation

a = - 1.20871 \dots, a = - 5.79128 \dots

Solution steps

a^{2} + 7 a + 7 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot 7}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot 7 = 21

a_{1, 2} = \frac{- 7 \pm 21}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- 7 + 21}{2 \cdot 1}, a_{2} = \frac{- 7 - 21}{2 \cdot 1}

a = \frac{- 7 + 21}{2 \cdot 1} : \frac{- 7 + 21}{2}

a = \frac{- 7 - 21}{2 \cdot 1} : \frac{- 7 - 21}{2}

The solutions to the quadratic equation are:

a = \frac{- 7 + 21}{2}, a = \frac{- 7 - 21}{2}

x^{2} = (5 \cdot 1 0^{- 9} - x) \cdot 1.862 \cdot 1 0^{- 10}

24 = w^{2} + 5 w

9.81 \cdot 2

- 5 (4 x - 2) = - 2 (3 + 6 x)

18 - \frac{324}{17}

What are the solutions to the equation a^2+7a+7=0 ?
The solutions to the equation a^2+7a+7=0 are a=(-7+sqrt(21))/2 ,a=(-7-sqrt(21))/2
Find the zeros of a^2+7a+7=0
The zeros of a^2+7a+7=0 are a=(-7+sqrt(21))/2 ,a=(-7-sqrt(21))/2