What is factor 1+x^2+2x ?

The solution to factor 1+x^2+2x is (x+1)^2

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factor 1+x^2+2x

factor

1 + x^{2} + 2 x

(x + 1)^{2}

Solution steps

1 + x^{2} + 2 x

Write in the standard form

= x^{2} + 2 x + 1

Rewrite in the form of

a^{2} + 2 ab + b^{2} :

1 = 1^{2}

2 x = 2 x \cdot 1

= x^{2} + 2 x \cdot 1 + 1^{2}

Apply Perfect Square Formula:

a^{2} + 2 ab + b^{2} = (a + b)^{2}

x^{2} + 2 x \cdot 1 + 1^{2} = (x + 1)^{2}

= (x + 1)^{2}

0.9 = (40 \cdot (x)) \cdot \frac{1}{0.000000823}

78 \geq 312

3 252 k^{5}

(a + b) (a + b)

2.5 (6 x - 4) = 10 + 4 (1.5 + 0.5 x)