What are the solutions to the equation (x-1)^2=5 ?

The solutions to the equation (x-1)^2=5 are x=sqrt(5)+1,x=-sqrt(5)+1

Find the zeros of (x-1)^2=5

The zeros of (x-1)^2=5 are x=sqrt(5)+1,x=-sqrt(5)+1

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(x - 1)^{2} = 5

x = 5 + 1, x = - 5 + 1

Solution steps

(x - 1)^{2} = 5

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 1 = 5 : x = 5 + 1

Solve

x - 1 = - 5 : x = - 5 + 1

The solutions to the quadratic equation are:

x = 5 + 1, x = - 5 + 1

9 = π r^{2} 16

a = 2 4^{2} + 2 0^{2}

\frac{2 ^{2}}{2 ^{- 2}}

1 < 4 x + 5 < 17

What are the solutions to the equation (x-1)^2=5 ?
The solutions to the equation (x-1)^2=5 are x=sqrt(5)+1,x=-sqrt(5)+1
Find the zeros of (x-1)^2=5
The zeros of (x-1)^2=5 are x=sqrt(5)+1,x=-sqrt(5)+1