What is ((i+1)^2)/((i+1)-1) ?

The solution to ((i+1)^2)/((i+1)-1) is 2

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simplify ((i+1)^2)/((i+1)-1)

simplify

\frac{( i + 1 ) ^{2}}{( i + 1 ) - 1}

2

Solution steps

\frac{( i + 1 ) ^{2}}{( i + 1 ) - 1}

Apply rule:

(a) = a

(i + 1) = i + 1

= \frac{( i + 1 ) ^{2}}{i + 1 - 1}

Expand

(i + 1)^{2} : 2 i

= \frac{2 i}{i + 1 - 1}

Subtract the numbers:

1 - 1 = 0

= \frac{2 i}{i}

Cancel the common factor:

i

= 2

(2)^{\frac{3}{2}}

\frac{2}{- 2}

(k + 2)^{2} = 16

- \frac{3}{2} + 2