What are the solutions to the equation x^2-18+25=0 ?

The solutions to the equation x^2-18+25=0 are x=sqrt(7)i,x=-sqrt(7)i

Find the zeros of x^2-18+25=0

The zeros of x^2-18+25=0 are x=sqrt(7)i,x=-sqrt(7)i

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x^{2} - 18 + 25 = 0

x = 7 i, x = - 7 i

Solution steps

x^{2} - 18 + 25 = 0

Move

18

to the right side

x^{2} + 25 = 18

Move

25

to the right side

x^{2} = - 7

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 7, x = - - 7

- 7 = 7 i

- - 7 = - 7 i

x = 7 i, x = - 7 i

\frac{∣ 3 x - 2 ∣}{∣ x + 1 ∣} < 4

3 (x - 2)^{2} (x + 5) = 3 (x + 1)^{2} (x - 1) + 3

- 3 (x - 3) > 5 - 5 x

- \frac{9 x}{x ^{2} - 5 x + 6} > \frac{( x ^{2} + 8 )}{x ^{2} - 5 x + 6}

\frac{1}{2} x^{2} - x + 5 = 0

What are the solutions to the equation x^2-18+25=0 ?
The solutions to the equation x^2-18+25=0 are x=sqrt(7)i,x=-sqrt(7)i
Find the zeros of x^2-18+25=0
The zeros of x^2-18+25=0 are x=sqrt(7)i,x=-sqrt(7)i