What is factor a^8-1 ?

The solution to factor a^8-1 is (a^4+1)(a^2+1)(a+1)(a-1)

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factor a^8-1

factor

a^{8} - 1

(a^{4} + 1) (a^{2} + 1) (a + 1) (a - 1)

Solution steps

a^{8} - 1

Apply exponent rules

= (a^{4})^{2} - 1^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(a^{4})^{2} - 1^{2} = (a^{4} + 1) (a^{4} - 1)

= (a^{4} + 1) (a^{4} - 1)

Factor

a^{4} - 1 : (a^{2} + 1) (a + 1) (a - 1)

= (a^{4} + 1) (a^{2} + 1) (a + 1) (a - 1)

- \frac{1}{2} (- 5)

lo g_{4} (\frac{1}{64}) = - 3

- 4 y = - 40

\frac{24 ( 4 - 1 ) ^{5}}{180 ( 10 ) ^{4}}

3 u^{3} + 7 u^{2} + 6 u + 14