What are the solutions to the equation r^2+15r+15=0 ?

The solutions to the equation r^2+15r+15=0 are r=(-15+sqrt(165))/2 ,r=(-15-sqrt(165))/2

Find the zeros of r^2+15r+15=0

The zeros of r^2+15r+15=0 are r=(-15+sqrt(165))/2 ,r=(-15-sqrt(165))/2

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r^{2} + 15 r + 15 = 0

r = \frac{- 15 + 165}{2}, r = \frac{- 15 - 165}{2}

Decimal

r = - 1.07738 \dots, r = - 13.92261 \dots

Solution steps

r^{2} + 15 r + 15 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 1 \cdot 15}{2 \cdot 1}

1 5^{2} - 4 \cdot 1 \cdot 15 = 165

r_{1, 2} = \frac{- 15 \pm 165}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- 15 + 165}{2 \cdot 1}, r_{2} = \frac{- 15 - 165}{2 \cdot 1}

r = \frac{- 15 + 165}{2 \cdot 1} : \frac{- 15 + 165}{2}

r = \frac{- 15 - 165}{2 \cdot 1} : \frac{- 15 - 165}{2}

The solutions to the quadratic equation are:

r = \frac{- 15 + 165}{2}, r = \frac{- 15 - 165}{2}

x^{2} + 3 x + 15 = 0

4 x^{2} + 13 x + 3 = 0

\frac{3 + 2 i}{1 - i}

3 - (- 3)^{4}

x^{4} + 2 x^{2} - 35

What are the solutions to the equation r^2+15r+15=0 ?
The solutions to the equation r^2+15r+15=0 are r=(-15+sqrt(165))/2 ,r=(-15-sqrt(165))/2
Find the zeros of r^2+15r+15=0
The zeros of r^2+15r+15=0 are r=(-15+sqrt(165))/2 ,r=(-15-sqrt(165))/2