What are the solutions to the equation a^2+2a+5=0 ?

The solutions to the equation a^2+2a+5=0 are a=-1+2i,a=-1-2i

Find the zeros of a^2+2a+5=0

The zeros of a^2+2a+5=0 are a=-1+2i,a=-1-2i

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a^{2} + 2 a + 5 = 0

a = - 1 + 2 i, a = - 1 - 2 i

Solution steps

a^{2} + 2 a + 5 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 5 : 4 i

a_{1, 2} = \frac{- 2 \pm 4 i}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- 2 + 4 i}{2 \cdot 1}, a_{2} = \frac{- 2 - 4 i}{2 \cdot 1}

a = \frac{- 2 + 4 i}{2 \cdot 1} : - 1 + 2 i

a = \frac{- 2 - 4 i}{2 \cdot 1} : - 1 - 2 i

The solutions to the quadratic equation are:

a = - 1 + 2 i, a = - 1 - 2 i

\frac{1}{2} \cdot 2

∣ 2 x - 6 ∣ > 10

- 6 (3 - 6 r) = - 18 + 4 r

(x + 6) (x - 2) = 20

\frac{- 7}{8} \leq m \frac{- 13}{8}

What are the solutions to the equation a^2+2a+5=0 ?
The solutions to the equation a^2+2a+5=0 are a=-1+2i,a=-1-2i
Find the zeros of a^2+2a+5=0
The zeros of a^2+2a+5=0 are a=-1+2i,a=-1-2i