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Popular >

5x^2-55x+150=0

Solution

5 x^{2} - 55 x + 150 = 0

Solution

x = 6, x = 5

Solution steps

5 x^{2} - 55 x + 150 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 55 ) \pm ( - 55 ) ^{2} - 4 \cdot 5 \cdot 150}{2 \cdot 5}

(- 55)^{2} - 4 \cdot 5 \cdot 150 = 5

x_{1, 2} = \frac{- ( - 55 ) \pm 5}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 55 ) + 5}{2 \cdot 5}, x_{2} = \frac{- ( - 55 ) - 5}{2 \cdot 5}

x = \frac{- ( - 55 ) + 5}{2 \cdot 5} : 6

x = \frac{- ( - 55 ) - 5}{2 \cdot 5} : 5

The solutions to the quadratic equation are:

x = 6, x = 5

Popular Examples

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4 x^{2} + 22 x + 10

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x^{2} - 2 + x^{2} + 5 x - 9 + (- 8 x - 42) + x = 360

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\frac{2}{5} + \frac{3}{4} \cdot \frac{1}{5} + 3 - \frac{7}{4}

22=1.5+(11^2+y^2)/(-19.6)

22 = 1.5 + \frac{1 1 ^{2} + y ^{2}}{- 19.6}

x^{2} + 9 x - 70 = 0

Frequently Asked Questions (FAQ)

What are the solutions to the equation 5x^2-55x+150=0 ?
The solutions to the equation 5x^2-55x+150=0 are x=6,x=5
Find the zeros of 5x^2-55x+150=0
The zeros of 5x^2-55x+150=0 are x=6,x=5