What are the solutions to the equation 324k^2+36k+1=0 ?

The solutions to the equation 324k^2+36k+1=0 are k=-1/18

Find the zeros of 324k^2+36k+1=0

The zeros of 324k^2+36k+1=0 are k=-1/18

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324 k^{2} + 36 k + 1 = 0

k = - \frac{1}{18}

Decimal Notation

k = - 0.05555 \dots

Solution steps

324 k^{2} + 36 k + 1 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 36 \pm 3 6 ^{2} - 4 \cdot 324 \cdot 1}{2 \cdot 324}

3 6^{2} - 4 \cdot 324 \cdot 1 = 0

k_{1, 2} = \frac{- 36 \pm 0}{2 \cdot 324}

k = \frac{- 36}{2 \cdot 324}

\frac{- 36}{2 \cdot 324} = - \frac{1}{18}

k = - \frac{1}{18}

The solution to the quadratic equation is:

k = - \frac{1}{18}

x + 10 = 2 x + 3

(x - 4) (x - 2) (x + 7) (x + 6) \leq 0

7 v + 23 = 4 v + 8 v - 22

x^{2} - 48 x + 576 = 0

5 \cdot \frac{1}{6}

What are the solutions to the equation 324k^2+36k+1=0 ?
The solutions to the equation 324k^2+36k+1=0 are k=-1/18
Find the zeros of 324k^2+36k+1=0
The zeros of 324k^2+36k+1=0 are k=-1/18