What are the solutions to the equation x^2-48x+576=0 ?

The solutions to the equation x^2-48x+576=0 are x=24

Find the zeros of x^2-48x+576=0

The zeros of x^2-48x+576=0 are x=24

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x^{2} - 48 x + 576 = 0

x = 24

Solution steps

x^{2} - 48 x + 576 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 48 ) \pm ( - 48 ) ^{2} - 4 \cdot 1 \cdot 576}{2 \cdot 1}

(- 48)^{2} - 4 \cdot 1 \cdot 576 = 0

x_{1, 2} = \frac{- ( - 48 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 48 )}{2 \cdot 1}

\frac{- ( - 48 )}{2 \cdot 1} = 24

x = 24

The solution to the quadratic equation is:

x = 24

5 \cdot \frac{1}{6}

- 16 x^{2} + 176 x = 0

12 (x - 4) = - 108

- 8 \cdot 2

What are the solutions to the equation x^2-48x+576=0 ?
The solutions to the equation x^2-48x+576=0 are x=24
Find the zeros of x^2-48x+576=0
The zeros of x^2-48x+576=0 are x=24