What are the solutions to the equation x^2-6x-41=0 ?

The solutions to the equation x^2-6x-41=0 are x=3+5sqrt(2),x=3-5sqrt(2)

Find the zeros of x^2-6x-41=0

The zeros of x^2-6x-41=0 are x=3+5sqrt(2),x=3-5sqrt(2)

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x^{2} - 6 x - 41 = 0

x = 3 + 52, x = 3 - 52

Decimal Notation

x = 10.07106 \dots, x = - 4.07106 \dots

Solution steps

x^{2} - 6 x - 41 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - 41 )}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot (- 41) = 102

x_{1, 2} = \frac{- ( - 6 ) \pm 10 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 10 2}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 10 2}{2 \cdot 1}

x = \frac{- ( - 6 ) + 10 2}{2 \cdot 1} : 3 + 52

x = \frac{- ( - 6 ) - 10 2}{2 \cdot 1} : 3 - 52

The solutions to the quadratic equation are:

x = 3 + 52, x = 3 - 52

x^{4} - 3 x^{2} - 4 \leq 0

\frac{4 ∣ x + 7 ∣}{3} < 8

- 7 (s + 2) - 12 = 37

9.817 = \frac{x}{360} π 5^{2}

a^{2} + 2^{2} = 4^{2}

What are the solutions to the equation x^2-6x-41=0 ?
The solutions to the equation x^2-6x-41=0 are x=3+5sqrt(2),x=3-5sqrt(2)
Find the zeros of x^2-6x-41=0
The zeros of x^2-6x-41=0 are x=3+5sqrt(2),x=3-5sqrt(2)