What are the solutions to the equation a^2+2^2=4^2 ?

The solutions to the equation a^2+2^2=4^2 are a=2sqrt(3),a=-2sqrt(3)

Find the zeros of a^2+2^2=4^2

The zeros of a^2+2^2=4^2 are a=2sqrt(3),a=-2sqrt(3)

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a^{2} + 2^{2} = 4^{2}

a = 23, a = - 23

Decimal Notation

a = 3.46410 \dots, a = - 3.46410 \dots

Solution steps

a^{2} + 2^{2} = 4^{2}

Move

2^{2}

to the right side

a^{2} = 12

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

a = 12, a = - 12

12 = 23

- 12 = - 23

a = 23, a = - 23

121 n^{2} - 66 n + 9

(\frac{a ^{2}}{b})^{5} (\frac{a ^{3} b ^{2}}{c ^{3}})^{3}

(4 - 7 i)^{2}

5 x - 5 = x + 11

What are the solutions to the equation a^2+2^2=4^2 ?
The solutions to the equation a^2+2^2=4^2 are a=2sqrt(3),a=-2sqrt(3)
Find the zeros of a^2+2^2=4^2
The zeros of a^2+2^2=4^2 are a=2sqrt(3),a=-2sqrt(3)