What are the solutions to the equation -y^2-13y=0 ?

The solutions to the equation -y^2-13y=0 are y=-13,y=0

Find the zeros of -y^2-13y=0

The zeros of -y^2-13y=0 are y=-13,y=0

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- y^{2} - 13 y = 0

y = - 13, y = 0

Solution steps

- y^{2} - 13 y = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 ( - 1 ) \cdot 0}{2 ( - 1 )}

(- 13)^{2} - 4 (- 1) \cdot 0 = 13

y_{1, 2} = \frac{- ( - 13 ) \pm 13}{2 ( - 1 )}

Separate the solutions

y_{1} = \frac{- ( - 13 ) + 13}{2 ( - 1 )}, y_{2} = \frac{- ( - 13 ) - 13}{2 ( - 1 )}

y = \frac{- ( - 13 ) + 13}{2 ( - 1 )} : - 13

y = \frac{- ( - 13 ) - 13}{2 ( - 1 )} : 0

The solutions to the quadratic equation are:

y = - 13, y = 0

\frac{x}{x ( x + y )} + \frac{1}{x} - \frac{y}{x + y}

\frac{3}{x} \leq \frac{4}{x + 1}

4 x^{2} = 10 + 3 x

\frac{1}{2 k} + \frac{4}{k} - \frac{k}{k + 2}

3 x + 21

What are the solutions to the equation -y^2-13y=0 ?
The solutions to the equation -y^2-13y=0 are y=-13,y=0
Find the zeros of -y^2-13y=0
The zeros of -y^2-13y=0 are y=-13,y=0