What is the answer to 2k(-3k+4)+6(k^2+10)=k(4k+8)-2k(2k+5) ?

The answer to 2k(-3k+4)+6(k^2+10)=k(4k+8)-2k(2k+5) is k=-6

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2k(-3k+4)+6(k^2+10)=k(4k+8)-2k(2k+5)

2 k (- 3 k + 4) + 6 (k^{2} + 10) = k (4 k + 8) - 2 k (2 k + 5)

k = - 6

Solution steps

2 k (- 3 k + 4) + 6 (k^{2} + 10) = k (4 k + 8) - 2 k (2 k + 5)

Expand

2 k (- 3 k + 4) + 6 (k^{2} + 10) : 8 k + 60

Expand

k (4 k + 8) - 2 k (2 k + 5) : - 2 k

8 k + 60 = - 2 k

Move

60

to the right side

8 k = - 2 k - 60

Move

2 k

to the left side

10 k = - 60

Divide both sides by

10

k = - 6

(1 - i) (- 2 + i)

- 14.5 = 0.5 x - 14.5

42 + y = 86

- 9 + 3 - 16

(\frac{a ^{4} b ^{3}}{2 a ^{3} b ^{4} \cdot 2 a ^{2} b ^{4}})^{3}

What is the answer to 2k(-3k+4)+6(k^2+10)=k(4k+8)-2k(2k+5) ?
The answer to 2k(-3k+4)+6(k^2+10)=k(4k+8)-2k(2k+5) is k=-6
Solve for k: 2k(-3k+4)+6(k^2+10)=k(4k+8)-2k(2k+5)
The solution is k=-6