What is (3+4i)-(6-10i) ?

The solution to (3+4i)-(6-10i) is -3+14i

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simplify (3+4i)-(6-10i)

simplify

(3 + 4 i) - (6 - 10 i)

- 3 + 14 i

Solution steps

(3 + 4 i) - (6 - 10 i)

Group the real part and the imaginary part of the complex number

(a + bi) - (c + d i) = (a - c) + (b - d) i

= (3 - 6) + (4 - (- 10)) i

Simplify

(3 - 6) + (4 - (- 10)) i : - 3 + 14 i

= - 3 + 14 i

\frac{16 !}{1 ! ( 16 - 1 ) !}

r^{2} + 4 r = 0

- 4 m + 2 = 7 m - 64

\frac{1}{4} + \frac{2}{7}

\frac{8 x y ^{3}}{- 4 x y ^{2}}