What are the solutions to the equation 200x-x^2=25x+6900 ?

The solutions to the equation 200x-x^2=25x+6900 are x=60,x=115

Find the zeros of 200x-x^2=25x+6900

The zeros of 200x-x^2=25x+6900 are x=60,x=115

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200 x - x^{2} = 25 x + 6900

x = 60, x = 115

Solution steps

200 x - x^{2} = 25 x + 6900

Move

6900

to the left side

200 x - x^{2} - 6900 = 25 x

Move

25 x

to the left side

- x^{2} + 175 x - 6900 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 175 \pm 17 5 ^{2} - 4 ( - 1 ) ( - 6900 )}{2 ( - 1 )}

17 5^{2} - 4 (- 1) (- 6900) = 55

x_{1, 2} = \frac{- 175 \pm 55}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 175 + 55}{2 ( - 1 )}, x_{2} = \frac{- 175 - 55}{2 ( - 1 )}

x = \frac{- 175 + 55}{2 ( - 1 )} : 60

x = \frac{- 175 - 55}{2 ( - 1 )} : 115

The solutions to the quadratic equation are:

x = 60, x = 115

4 s - 2 s = 18

\frac{3 π}{2} + \frac{π}{3}

\frac{2 x + 1}{3 x - 6} \leq 3

18 (x - 3)^{2} + 9 (x - 3) - 2 = 0

- 6 + 9 i

What are the solutions to the equation 200x-x^2=25x+6900 ?
The solutions to the equation 200x-x^2=25x+6900 are x=60,x=115
Find the zeros of 200x-x^2=25x+6900
The zeros of 200x-x^2=25x+6900 are x=60,x=115