What are the solutions to the equation b^2-16=0 ?

The solutions to the equation b^2-16=0 are b=4,b=-4

Find the zeros of b^2-16=0

The zeros of b^2-16=0 are b=4,b=-4

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b^{2} - 16 = 0

b = 4, b = - 4

Solution steps

b^{2} - 16 = 0

Move

16

to the right side

b^{2} = 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 16, b = - 16

16 = 4

- 16 = - 4

b = 4, b = - 4

3 x - 91 > - 87 or 21 x - 17 > 25

(\frac{1}{3})^{4} (- 3)^{2}

6 x^{2} - 11 x + 20 = 2 - 95 x

3 n^{2} + 5 n + 2

8 x^{2} + 7 x + 1 = 0

What are the solutions to the equation b^2-16=0 ?
The solutions to the equation b^2-16=0 are b=4,b=-4
Find the zeros of b^2-16=0
The zeros of b^2-16=0 are b=4,b=-4