What are the solutions to the equation 6x^2-11x+20=2-95x ?

The solutions to the equation 6x^2-11x+20=2-95x are x=-7+sqrt(46),x=-7-sqrt(46)

Find the zeros of 6x^2-11x+20=2-95x

The zeros of 6x^2-11x+20=2-95x are x=-7+sqrt(46),x=-7-sqrt(46)

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6 x^{2} - 11 x + 20 = 2 - 95 x

x = - 7 + 46, x = - 7 - 46

Decimal Notation

x = - 0.21767 \dots, x = - 13.78232 \dots

Solution steps

6 x^{2} - 11 x + 20 = 2 - 95 x

Move

95 x

to the left side

6 x^{2} + 84 x + 20 = 2

Move

2

to the left side

6 x^{2} + 84 x + 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 84 \pm 8 4 ^{2} - 4 \cdot 6 \cdot 18}{2 \cdot 6}

8 4^{2} - 4 \cdot 6 \cdot 18 = 1246

x_{1, 2} = \frac{- 84 \pm 12 46}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 84 + 12 46}{2 \cdot 6}, x_{2} = \frac{- 84 - 12 46}{2 \cdot 6}

x = \frac{- 84 + 12 46}{2 \cdot 6} : - 7 + 46

x = \frac{- 84 - 12 46}{2 \cdot 6} : - 7 - 46

The solutions to the quadratic equation are:

x = - 7 + 46, x = - 7 - 46

3 n^{2} + 5 n + 2

8 x^{2} + 7 x + 1 = 0

h^{2} + 10 h - 37 = 0

2 x^{2} + 12 x + 18 = 0

2 x - 1 < \frac{3 x}{2} < x + 1

What are the solutions to the equation 6x^2-11x+20=2-95x ?
The solutions to the equation 6x^2-11x+20=2-95x are x=-7+sqrt(46),x=-7-sqrt(46)
Find the zeros of 6x^2-11x+20=2-95x
The zeros of 6x^2-11x+20=2-95x are x=-7+sqrt(46),x=-7-sqrt(46)