What are the solutions to the equation 3x^2+12x+10=0 ?

The solutions to the equation 3x^2+12x+10=0 are x=(-6+sqrt(6))/3 ,x=-(2sqrt(3)+sqrt(2))/(sqrt(3))

Find the zeros of 3x^2+12x+10=0

The zeros of 3x^2+12x+10=0 are x=(-6+sqrt(6))/3 ,x=-(2sqrt(3)+sqrt(2))/(sqrt(3))

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3 x^{2} + 12 x + 10 = 0

x = \frac{- 6 + 6}{3}, x = - \frac{2 3 + 2}{3}

Decimal Notation

x = - 1.18350 \dots, x = - 2.81649 \dots

Solution steps

3 x^{2} + 12 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 3 \cdot 10}{2 \cdot 3}

1 2^{2} - 4 \cdot 3 \cdot 10 = 26

x_{1, 2} = \frac{- 12 \pm 2 6}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 12 + 2 6}{2 \cdot 3}, x_{2} = \frac{- 12 - 2 6}{2 \cdot 3}

x = \frac{- 12 + 2 6}{2 \cdot 3} : \frac{- 6 + 6}{3}

x = \frac{- 12 - 2 6}{2 \cdot 3} : - \frac{2 3 + 2}{3}

The solutions to the quadratic equation are:

x = \frac{- 6 + 6}{3}, x = - \frac{2 3 + 2}{3}

\frac{2 x - 5}{9} = 3

∣ 5 x + 2 ∣ \leq 3

2 (4 k^{2} - 2 k) - 3 (- 6 k^{2} + 4) + 2 k (k - 1)

45 a^{4} - 30 a^{3} + 5 a^{2}

- \frac{1}{2} x \geq 4

What are the solutions to the equation 3x^2+12x+10=0 ?
The solutions to the equation 3x^2+12x+10=0 are x=(-6+sqrt(6))/3 ,x=-(2sqrt(3)+sqrt(2))/(sqrt(3))
Find the zeros of 3x^2+12x+10=0
The zeros of 3x^2+12x+10=0 are x=(-6+sqrt(6))/3 ,x=-(2sqrt(3)+sqrt(2))/(sqrt(3))