What are the solutions to the equation 12x^2-15x-6=0 ?

The solutions to the equation 12x^2-15x-6=0 are x=(5+sqrt(57))/8 ,x=(5-sqrt(57))/8

Find the zeros of 12x^2-15x-6=0

The zeros of 12x^2-15x-6=0 are x=(5+sqrt(57))/8 ,x=(5-sqrt(57))/8

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12 x^{2} - 15 x - 6 = 0

x = \frac{5 + 57}{8}, x = \frac{5 - 57}{8}

Decimal Notation

x = 1.56872 \dots, x = - 0.31872 \dots

Solution steps

12 x^{2} - 15 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 12 ( - 6 )}{2 \cdot 12}

(- 15)^{2} - 4 \cdot 12 (- 6) = 357

x_{1, 2} = \frac{- ( - 15 ) \pm 3 57}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 15 ) + 3 57}{2 \cdot 12}, x_{2} = \frac{- ( - 15 ) - 3 57}{2 \cdot 12}

x = \frac{- ( - 15 ) + 3 57}{2 \cdot 12} : \frac{5 + 57}{8}

x = \frac{- ( - 15 ) - 3 57}{2 \cdot 12} : \frac{5 - 57}{8}

The solutions to the quadratic equation are:

x = \frac{5 + 57}{8}, x = \frac{5 - 57}{8}

3 y^{2} - y = 2

2^{22}

3 x = - 18

∣ x ∣ = 17

\frac{5 b - 10}{b ^{2} + 5 b - 14}

What are the solutions to the equation 12x^2-15x-6=0 ?
The solutions to the equation 12x^2-15x-6=0 are x=(5+sqrt(57))/8 ,x=(5-sqrt(57))/8
Find the zeros of 12x^2-15x-6=0
The zeros of 12x^2-15x-6=0 are x=(5+sqrt(57))/8 ,x=(5-sqrt(57))/8