What are the solutions to the equation 2x^2-32x=0 ?

The solutions to the equation 2x^2-32x=0 are x=16,x=0

Find the zeros of 2x^2-32x=0

The zeros of 2x^2-32x=0 are x=16,x=0

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2 x^{2} - 32 x = 0

x = 16, x = 0

Solution steps

2 x^{2} - 32 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 32 ) \pm ( - 32 ) ^{2} - 4 \cdot 2 \cdot 0}{2 \cdot 2}

(- 32)^{2} - 4 \cdot 2 \cdot 0 = 32

x_{1, 2} = \frac{- ( - 32 ) \pm 32}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 32 ) + 32}{2 \cdot 2}, x_{2} = \frac{- ( - 32 ) - 32}{2 \cdot 2}

x = \frac{- ( - 32 ) + 32}{2 \cdot 2} : 16

x = \frac{- ( - 32 ) - 32}{2 \cdot 2} : 0

The solutions to the quadratic equation are:

x = 16, x = 0

5 x^{2} - 45 x + 70

\frac{x + 5}{9} - \frac{x + 2}{5} = 1

2 x < 10 - 3 x

(x^{\frac{3}{4}})^{\frac{2}{3}}

3 x^{2} - 10 x = - 2

What are the solutions to the equation 2x^2-32x=0 ?
The solutions to the equation 2x^2-32x=0 are x=16,x=0
Find the zeros of 2x^2-32x=0
The zeros of 2x^2-32x=0 are x=16,x=0