What are the solutions to the equation 3x^2-10x=-2 ?

The solutions to the equation 3x^2-10x=-2 are x=(5+sqrt(19))/3 ,x=(5-sqrt(19))/3

Find the zeros of 3x^2-10x=-2

The zeros of 3x^2-10x=-2 are x=(5+sqrt(19))/3 ,x=(5-sqrt(19))/3

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3 x^{2} - 10 x = - 2

x = \frac{5 + 19}{3}, x = \frac{5 - 19}{3}

Solution steps

3 x^{2} - 10 x = - 2

Move

2

to the left side

3 x^{2} - 10 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 3 \cdot 2}{2 \cdot 3}

(- 10)^{2} - 4 \cdot 3 \cdot 2 = 219

x_{1, 2} = \frac{- ( - 10 ) \pm 2 19}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2 19}{2 \cdot 3}, x_{2} = \frac{- ( - 10 ) - 2 19}{2 \cdot 3}

x = \frac{- ( - 10 ) + 2 19}{2 \cdot 3} : \frac{5 + 19}{3}

x = \frac{- ( - 10 ) - 2 19}{2 \cdot 3} : \frac{5 - 19}{3}

The solutions to the quadratic equation are:

x = \frac{5 + 19}{3}, x = \frac{5 - 19}{3}

(x - 5) (x - 7) = 0

\frac{x ^{2} + 1}{x} > 0

4 h + 2 \geq 10

- 8 - 4

3 x^{2} + 24 x + 54 = 6

What are the solutions to the equation 3x^2-10x=-2 ?
The solutions to the equation 3x^2-10x=-2 are x=(5+sqrt(19))/3 ,x=(5-sqrt(19))/3
Find the zeros of 3x^2-10x=-2
The zeros of 3x^2-10x=-2 are x=(5+sqrt(19))/3 ,x=(5-sqrt(19))/3