What are the solutions to the equation (x+12)^2=25 ?

The solutions to the equation (x+12)^2=25 are x=-7,x=-17

Find the zeros of (x+12)^2=25

The zeros of (x+12)^2=25 are x=-7,x=-17

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x + 12)^{2} = 25

x = - 7, x = - 17

Solution steps

(x + 12)^{2} = 25

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 12 = 25 : x = - 7

Solve

x + 12 = - 25 : x = - 17

The solutions to the quadratic equation are:

x = - 7, x = - 17

15 x = 0

9 x^{2} - 2 x - 1 = 0

- 75 + 63

\frac{( - 8 x ^{3} y ^{2} ) ^{2} \cdot 2 x ^{2} y ^{6}}{32 x ^{8} y ^{3}}

b^{3} + 3 b^{2} - 4 b - 12

What are the solutions to the equation (x+12)^2=25 ?
The solutions to the equation (x+12)^2=25 are x=-7,x=-17
Find the zeros of (x+12)^2=25
The zeros of (x+12)^2=25 are x=-7,x=-17