What are the solutions to the equation z^2+3z-18=0 ?

The solutions to the equation z^2+3z-18=0 are z=3,z=-6

Find the zeros of z^2+3z-18=0

The zeros of z^2+3z-18=0 are z=3,z=-6

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z^{2} + 3 z - 18 = 0

z = 3, z = - 6

Solution steps

z^{2} + 3 z - 18 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 18 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 18) = 9

z_{1, 2} = \frac{- 3 \pm 9}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- 3 + 9}{2 \cdot 1}, z_{2} = \frac{- 3 - 9}{2 \cdot 1}

z = \frac{- 3 + 9}{2 \cdot 1} : 3

z = \frac{- 3 - 9}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

z = 3, z = - 6

(x)^{- 2} (16 x^{3}) (8^{\frac{2}{3}})^{- 1}

4 d - 11 = 2 d + 7

3 x^{2} = - 21

x^{2} - 3 x < 2 x^{2} - 5 x + 6

x^{3} - x^{2} - 9 x + 9

What are the solutions to the equation z^2+3z-18=0 ?
The solutions to the equation z^2+3z-18=0 are z=3,z=-6
Find the zeros of z^2+3z-18=0
The zeros of z^2+3z-18=0 are z=3,z=-6