What are the solutions to the equation x^2-7x-20=0 ?

The solutions to the equation x^2-7x-20=0 are x=(7+sqrt(129))/2 ,x=(7-sqrt(129))/2

Find the zeros of x^2-7x-20=0

The zeros of x^2-7x-20=0 are x=(7+sqrt(129))/2 ,x=(7-sqrt(129))/2

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x^{2} - 7 x - 20 = 0

x = \frac{7 + 129}{2}, x = \frac{7 - 129}{2}

Decimal Notation

x = 9.17890 \dots, x = - 2.17890 \dots

Solution steps

x^{2} - 7 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot ( - 20 )}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot (- 20) = 129

x_{1, 2} = \frac{- ( - 7 ) \pm 129}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 129}{2 \cdot 1}, x_{2} = \frac{- ( - 7 ) - 129}{2 \cdot 1}

x = \frac{- ( - 7 ) + 129}{2 \cdot 1} : \frac{7 + 129}{2}

x = \frac{- ( - 7 ) - 129}{2 \cdot 1} : \frac{7 - 129}{2}

The solutions to the quadratic equation are:

x = \frac{7 + 129}{2}, x = \frac{7 - 129}{2}

2 x + 2 = x + 11

3 (x - 2) - 5 (2 x - 1) - 2 (3 x + 4) + 10 = 0

2 x = 2

3 - (\frac{1}{2})

p^{6} q^{4} - q^{7}

What are the solutions to the equation x^2-7x-20=0 ?
The solutions to the equation x^2-7x-20=0 are x=(7+sqrt(129))/2 ,x=(7-sqrt(129))/2
Find the zeros of x^2-7x-20=0
The zeros of x^2-7x-20=0 are x=(7+sqrt(129))/2 ,x=(7-sqrt(129))/2