What are the solutions to the equation 45=-2(x+7)^2 ?

The solutions to the equation 45=-2(x+7)^2 are x=-7+i(3sqrt(10))/2 ,x=-7-i(3sqrt(10))/2

Find the zeros of 45=-2(x+7)^2

The zeros of 45=-2(x+7)^2 are x=-7+i(3sqrt(10))/2 ,x=-7-i(3sqrt(10))/2

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45 = - 2 (x + 7)^{2}

x = - 7 + i \frac{3 10}{2}, x = - 7 - i \frac{3 10}{2}

Solution steps

45 = - 2 (x + 7)^{2}

Switch sides

- 2 (x + 7)^{2} = 45

Divide both sides by

- 2

(x + 7)^{2} = - \frac{45}{2}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 7 = - \frac{45}{2} : x = - 7 + i \frac{3 10}{2}

Solve

x + 7 = - - \frac{45}{2} : x = - 7 - i \frac{3 10}{2}

The solutions to the quadratic equation are:

x = - 7 + i \frac{3 10}{2}, x = - 7 - i \frac{3 10}{2}

5 x^{2} - 22 x - 15

∣ x + 1 ∣ = x^{2} - 5

y = y (1 - y)

8 x^{2} - 10 x - 7 = 0

What are the solutions to the equation 45=-2(x+7)^2 ?
The solutions to the equation 45=-2(x+7)^2 are x=-7+i(3sqrt(10))/2 ,x=-7-i(3sqrt(10))/2
Find the zeros of 45=-2(x+7)^2
The zeros of 45=-2(x+7)^2 are x=-7+i(3sqrt(10))/2 ,x=-7-i(3sqrt(10))/2