What is factor (2x-y)^2-(x-z)^2 ?

The solution to factor (2x-y)^2-(x-z)^2 is (3x-y-z)(x-y+z)

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factor (2x-y)^2-(x-z)^2

factor

(2 x - y)^{2} - (x - z)^{2}

(3 x - y - z) (x - y + z)

Solution steps

(2 x - y)^{2} - (x - z)^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(2 x - y)^{2} - (x - z)^{2} = ((2 x - y) + (x - z)) ((2 x - y) - (x - z))

= ((2 x - y) + (x - z)) ((2 x - y) - (x - z))

Simplify

((2 x - y) + (x - z)) ((2 x - y) - (x - z)) : (3 x - y - z) (x - y + z)

= (3 x - y - z) (x - y + z)

3 x - 5 + x < 4 - 2 x - 7

\frac{x - y i}{x + y i + 1}

\frac{2}{7} \times \frac{3}{4}

x^{2} - 12 x - 45

5 x^{2} + 2 x + 5 = 0

What is factor (2x-y)^2-(x-z)^2 ?
The solution to factor (2x-y)^2-(x-z)^2 is (3x-y-z)(x-y+z)