What is ((10g^{-4}h^7t^{15})/(24h^{-3)t^8})^{-4} ?

The solution to ((10g^{-4}h^7t^{15})/(24h^{-3)t^8})^{-4} is (20736g^{16})/(625h^{40)t^{28}}

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simplify ((10g^{-4}h^7t^{15})/(24h^{-3)t^8})^{-4}

simplify

(\frac{10 g ^{- 4} h ^{7} t ^{15}}{24 h ^{- 3} t ^{8}})^{- 4}

\frac{20736 g ^{16}}{625 h ^{40} t ^{28}}

Solution steps

(\frac{10 g ^{- 4} h ^{7} t ^{15}}{24 h ^{- 3} t ^{8}})^{- 4}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(\frac{10 g ^{- 4} h ^{7} t ^{15}}{24 h ^{- 3} t ^{8}})^{- 4} = \frac{1}{( \frac{10 g ^{- 4} h ^{7} t ^{15}}{24 h ^{- 3} t ^{8}} ) ^{4}}

= \frac{1}{( \frac{10 g ^{- 4} h ^{7} t ^{15}}{24 h ^{- 3} t ^{8}} ) ^{4}}

Simplify

(\frac{10 g ^{- 4} h ^{7} t ^{15}}{24 h ^{- 3} t ^{8}})^{4} : \frac{625 h ^{40} t ^{28}}{20736 g ^{16}}

= \frac{1}{\frac{625 h ^{40} t ^{28}}{20736 g ^{16}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{20736 g ^{16}}{625 h ^{40} t ^{28}}

2 x - 14

m n^{2} \cdot m^{2} n^{- 4} \cdot m n^{- 1}

2 x^{2} - 9 x + 5 = 0

\frac{x - 1}{3} = 3

\frac{a ^{3} b ^{5}}{a b ^{2}}

What is ((10g^{-4}h^7t^{15})/(24h^{-3)t^8})^{-4} ?
The solution to ((10g^{-4}h^7t^{15})/(24h^{-3)t^8})^{-4} is (20736g^{16})/(625h^{40)t^{28}}