What is factor m^2+4m-12 ?

The solution to factor m^2+4m-12 is (m-2)(m+6)

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factor m^2+4m-12

factor

m^{2} + 4 m - 12

(m - 2) (m + 6)

Solution steps

m^{2} + 4 m - 12

Break the expression into groups

= (m^{2} - 2 m) + (6 m - 12)

Factor out

m

from

m^{2} - 2 m : m (m - 2)

Factor out

6

from

6 m - 12 : 6 (m - 2)

= m (m - 2) + 6 (m - 2)

Factor out common term

m - 2

= (m - 2) (m + 6)

4 x^{2} - 19 x - 5

\frac{1}{2} (x^{2} + h) x

(z^{- \frac{4}{3}})^{- \frac{6}{5}}

4 n^{2} - 20 n + 25

6 x - 18 = 4 x + 23