What are the solutions to the equation 2x^2-9x-6=0 ?

The solutions to the equation 2x^2-9x-6=0 are x=(9+sqrt(129))/4 ,x=(9-sqrt(129))/4

Find the zeros of 2x^2-9x-6=0

The zeros of 2x^2-9x-6=0 are x=(9+sqrt(129))/4 ,x=(9-sqrt(129))/4

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2 x^{2} - 9 x - 6 = 0

x = \frac{9 + 129}{4}, x = \frac{9 - 129}{4}

Decimal Notation

x = 5.08945 \dots, x = - 0.58945 \dots

Solution steps

2 x^{2} - 9 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 2 ( - 6 )}{2 \cdot 2}

(- 9)^{2} - 4 \cdot 2 (- 6) = 129

x_{1, 2} = \frac{- ( - 9 ) \pm 129}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 129}{2 \cdot 2}, x_{2} = \frac{- ( - 9 ) - 129}{2 \cdot 2}

x = \frac{- ( - 9 ) + 129}{2 \cdot 2} : \frac{9 + 129}{4}

x = \frac{- ( - 9 ) - 129}{2 \cdot 2} : \frac{9 - 129}{4}

The solutions to the quadratic equation are:

x = \frac{9 + 129}{4}, x = \frac{9 - 129}{4}

\frac{w}{4} + 68 < 67

\frac{x + 9}{2} + 3 = 2

4 - (7 x + 7) = \frac{3}{2} (- 9 x + \frac{2}{3}) + x

12

x^{2} + 11 x = - 5 x - 60

What are the solutions to the equation 2x^2-9x-6=0 ?
The solutions to the equation 2x^2-9x-6=0 are x=(9+sqrt(129))/4 ,x=(9-sqrt(129))/4
Find the zeros of 2x^2-9x-6=0
The zeros of 2x^2-9x-6=0 are x=(9+sqrt(129))/4 ,x=(9-sqrt(129))/4