What are the solutions to the equation 4x-x^2=-6x ?

The solutions to the equation 4x-x^2=-6x are x=0,x=10

Find the zeros of 4x-x^2=-6x

The zeros of 4x-x^2=-6x are x=0,x=10

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4 x - x^{2} = - 6 x

x = 0, x = 10

Solution steps

4 x - x^{2} = - 6 x

Move

6 x

to the left side

- x^{2} + 10 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 ( - 1 ) \cdot 0}{2 ( - 1 )}

1 0^{2} - 4 (- 1) \cdot 0 = 10

x_{1, 2} = \frac{- 10 \pm 10}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 10 + 10}{2 ( - 1 )}, x_{2} = \frac{- 10 - 10}{2 ( - 1 )}

x = \frac{- 10 + 10}{2 ( - 1 )} : 0

x = \frac{- 10 - 10}{2 ( - 1 )} : 10

The solutions to the quadratic equation are:

x = 0, x = 10

34

\frac{5}{8} - \frac{3}{4} t = \frac{7}{8}

x^{2} - \frac{1}{2} x + \frac{2}{3}

∣ 7 x + 42 ∣ \leq 0

∣ k - 10 ∣ = 3

What are the solutions to the equation 4x-x^2=-6x ?
The solutions to the equation 4x-x^2=-6x are x=0,x=10
Find the zeros of 4x-x^2=-6x
The zeros of 4x-x^2=-6x are x=0,x=10