What are the solutions to the equation x^2-8x-1=0 ?

The solutions to the equation x^2-8x-1=0 are x=4+sqrt(17),x=4-sqrt(17)

Find the zeros of x^2-8x-1=0

The zeros of x^2-8x-1=0 are x=4+sqrt(17),x=4-sqrt(17)

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x^{2} - 8 x - 1 = 0

x = 4 + 17, x = 4 - 17

Solution steps

x^{2} - 8 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot ( - 1 )}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot (- 1) = 217

x_{1, 2} = \frac{- ( - 8 ) \pm 2 17}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2 17}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 2 17}{2 \cdot 1}

x = \frac{- ( - 8 ) + 2 17}{2 \cdot 1} : 4 + 17

x = \frac{- ( - 8 ) - 2 17}{2 \cdot 1} : 4 - 17

The solutions to the quadratic equation are:

x = 4 + 17, x = 4 - 17

(\frac{2}{3} - \frac{5}{9})^{2}

x^{2} - 10 x - 25 = 0

(x + 5) \cdot (x - 4) \leq 6

a^{2} + 14 a + 45

5 - 4 x \geq 3 x - 9

What are the solutions to the equation x^2-8x-1=0 ?
The solutions to the equation x^2-8x-1=0 are x=4+sqrt(17),x=4-sqrt(17)
Find the zeros of x^2-8x-1=0
The zeros of x^2-8x-1=0 are x=4+sqrt(17),x=4-sqrt(17)