What are the solutions to the equation (2x-7)^2=8 ?

The solutions to the equation (2x-7)^2=8 are x=(2sqrt(2)+7)/2 ,x=(-2sqrt(2)+7)/2

Find the zeros of (2x-7)^2=8

The zeros of (2x-7)^2=8 are x=(2sqrt(2)+7)/2 ,x=(-2sqrt(2)+7)/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(2 x - 7)^{2} = 8

x = \frac{2 2 + 7}{2}, x = \frac{- 2 2 + 7}{2}

Decimal Notation

x = 4.91421 \dots, x = 2.08578 \dots

Solution steps

(2 x - 7)^{2} = 8

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x - 7 = 8 : x = \frac{2 2 + 7}{2}

Solve

2 x - 7 = - 8 : x = \frac{- 2 2 + 7}{2}

The solutions to the quadratic equation are:

x = \frac{2 2 + 7}{2}, x = \frac{- 2 2 + 7}{2}

5 k - 2 k > - 9

∣ t + 2 ∣ = 0

\frac{x - 2}{2} + \frac{x - 3}{3} + \frac{x - 4}{4} = 10

6.3 (2 y) + 9.6 y = 637.5

x^{2} + 7 x y - 44 y^{2}

What are the solutions to the equation (2x-7)^2=8 ?
The solutions to the equation (2x-7)^2=8 are x=(2sqrt(2)+7)/2 ,x=(-2sqrt(2)+7)/2
Find the zeros of (2x-7)^2=8
The zeros of (2x-7)^2=8 are x=(2sqrt(2)+7)/2 ,x=(-2sqrt(2)+7)/2